Hello,
can someone explain how to unzip with rexx and possibly zip as well?
( unzip32.dll )
//Jan-Erik
Hi jep...
???
Since you know about the existence of the dll... you should have this (see below) too
That's from the InfoZip source distro, subfolder "OS2", file "rexxtest.cmd":
/* Test REXX UnZip API */
call RxFuncAdd 'UZLoadFuncs', 'UNZIP32', 'UZLoadFuncs'
call UZLoadFuncs
parse arg all
say; say 'Demonstrating UZUnZip' UZUnZip(all,'TEST.')
do num=1 to test.0
say num':'test.num
end
/*** Demonstrate UZFileTree ***/
fname = 'g:\cqc\channel1\12-30.qwk'
say; say 'Demonstrating UZFileTree by displaying all entries in',
fname
exc.0 = 2
exc.1 = '*.dat'
exc.2 = '*.ndx'
call UZFileTree fname, 'files','','exc'
do num=1 to files.0
say num':'files.num
end
say; say 'Demonstrating UZUnZipToVar -' UZUnZipToVar(fname,'CONTROL.DAT')
test. = 0
say; say 'Demonstrating UZUnZipToVar -' UZUnZipToVar(fname,'CONTROL.DAT','test.')
SAY "Test =" test.0
do num=1 to test.0
say num':'test.num
end
test. = 0
say; say 'Demonstrating UZUnZipToStem -' UZUnZipToStem('\SourceCode\cqc\cqcmain.zip','test',"*.rch",,'T')
call recout "test"
say; say 'Demonstrating UZVer -' UZVer()
call UZDropFuncs
exit
recout: PROCEDURE EXPOSE test.
parse arg this
say this "Contains" value(this'.0') "entries"
do num=1 to value(this'.0')
tval = value(this'.'num)
say "Got" this'.'num':' tval
if Right(tval,1) = '/' then
call recout this'.'left(tval,length(tval)-1)
else
say "Contains:" value(this'.tval')
end
return
Unzip source at SourceForge:
http://sourceforge.net/project/showfiles.php?group_id=118012&package_id=128992 (http://sourceforge.net/project/showfiles.php?group_id=118012&package_id=128992)
Zip source at SourceForge:
http://sourceforge.net/project/showfiles.php?group_id=118012&package_id=128993 (http://sourceforge.net/project/showfiles.php?group_id=118012&package_id=128993)
(Didn't find rexx sample for zip though, however no time left, will call back...)
Cheers! ;-)
Thomas